Optimal. Leaf size=142 \[ \frac{7 \sqrt{5 x+3} (3 x+2)^4}{33 (1-2 x)^{3/2}}-\frac{2051 \sqrt{5 x+3} (3 x+2)^3}{726 \sqrt{1-2 x}}-\frac{23909 \sqrt{1-2 x} \sqrt{5 x+3} (3 x+2)^2}{4840}-\frac{\sqrt{1-2 x} \sqrt{5 x+3} (50124540 x+120791143)}{774400}+\frac{8261577 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{6400 \sqrt{10}} \]
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Rubi [A] time = 0.0424436, antiderivative size = 142, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {98, 150, 153, 147, 54, 216} \[ \frac{7 \sqrt{5 x+3} (3 x+2)^4}{33 (1-2 x)^{3/2}}-\frac{2051 \sqrt{5 x+3} (3 x+2)^3}{726 \sqrt{1-2 x}}-\frac{23909 \sqrt{1-2 x} \sqrt{5 x+3} (3 x+2)^2}{4840}-\frac{\sqrt{1-2 x} \sqrt{5 x+3} (50124540 x+120791143)}{774400}+\frac{8261577 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{6400 \sqrt{10}} \]
Antiderivative was successfully verified.
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Rule 98
Rule 150
Rule 153
Rule 147
Rule 54
Rule 216
Rubi steps
\begin{align*} \int \frac{(2+3 x)^5}{(1-2 x)^{5/2} \sqrt{3+5 x}} \, dx &=\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}-\frac{1}{33} \int \frac{(2+3 x)^3 \left (281+\frac{927 x}{2}\right )}{(1-2 x)^{3/2} \sqrt{3+5 x}} \, dx\\ &=-\frac{2051 (2+3 x)^3 \sqrt{3+5 x}}{726 \sqrt{1-2 x}}+\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}-\frac{1}{363} \int \frac{\left (-32787-\frac{215181 x}{4}\right ) (2+3 x)^2}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx\\ &=-\frac{23909 \sqrt{1-2 x} (2+3 x)^2 \sqrt{3+5 x}}{4840}-\frac{2051 (2+3 x)^3 \sqrt{3+5 x}}{726 \sqrt{1-2 x}}+\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}+\frac{\int \frac{(2+3 x) \left (\frac{11526957}{4}+\frac{37593405 x}{8}\right )}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{10890}\\ &=-\frac{23909 \sqrt{1-2 x} (2+3 x)^2 \sqrt{3+5 x}}{4840}-\frac{2051 (2+3 x)^3 \sqrt{3+5 x}}{726 \sqrt{1-2 x}}+\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}-\frac{\sqrt{1-2 x} \sqrt{3+5 x} (120791143+50124540 x)}{774400}+\frac{8261577 \int \frac{1}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{12800}\\ &=-\frac{23909 \sqrt{1-2 x} (2+3 x)^2 \sqrt{3+5 x}}{4840}-\frac{2051 (2+3 x)^3 \sqrt{3+5 x}}{726 \sqrt{1-2 x}}+\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}-\frac{\sqrt{1-2 x} \sqrt{3+5 x} (120791143+50124540 x)}{774400}+\frac{8261577 \operatorname{Subst}\left (\int \frac{1}{\sqrt{11-2 x^2}} \, dx,x,\sqrt{3+5 x}\right )}{6400 \sqrt{5}}\\ &=-\frac{23909 \sqrt{1-2 x} (2+3 x)^2 \sqrt{3+5 x}}{4840}-\frac{2051 (2+3 x)^3 \sqrt{3+5 x}}{726 \sqrt{1-2 x}}+\frac{7 (2+3 x)^4 \sqrt{3+5 x}}{33 (1-2 x)^{3/2}}-\frac{\sqrt{1-2 x} \sqrt{3+5 x} (120791143+50124540 x)}{774400}+\frac{8261577 \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{3+5 x}\right )}{6400 \sqrt{10}}\\ \end{align*}
Mathematica [A] time = 0.0746912, size = 79, normalized size = 0.56 \[ \frac{2998952451 \sqrt{10-20 x} (2 x-1) \sin ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )-10 \sqrt{5 x+3} \left (18817920 x^4+101146320 x^3+359461476 x^2-1261070176 x+452899509\right )}{23232000 (1-2 x)^{3/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.013, size = 154, normalized size = 1.1 \begin{align*}{\frac{1}{46464000\, \left ( 2\,x-1 \right ) ^{2}} \left ( -376358400\,{x}^{4}\sqrt{-10\,{x}^{2}-x+3}+11995809804\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ){x}^{2}-2022926400\,{x}^{3}\sqrt{-10\,{x}^{2}-x+3}-11995809804\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) x-7189229520\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}+2998952451\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) +25221403520\,x\sqrt{-10\,{x}^{2}-x+3}-9057990180\,\sqrt{-10\,{x}^{2}-x+3} \right ) \sqrt{3+5\,x}\sqrt{1-2\,x}{\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.61691, size = 146, normalized size = 1.03 \begin{align*} -\frac{81}{40} \, \sqrt{-10 \, x^{2} - x + 3} x^{2} + \frac{8261577}{128000} \, \sqrt{5} \sqrt{2} \arcsin \left (\frac{20}{11} \, x + \frac{1}{11}\right ) - \frac{4131}{320} \, \sqrt{-10 \, x^{2} - x + 3} x - \frac{326943}{6400} \, \sqrt{-10 \, x^{2} - x + 3} + \frac{16807 \, \sqrt{-10 \, x^{2} - x + 3}}{528 \,{\left (4 \, x^{2} - 4 \, x + 1\right )}} + \frac{1020425 \, \sqrt{-10 \, x^{2} - x + 3}}{5808 \,{\left (2 \, x - 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.55128, size = 348, normalized size = 2.45 \begin{align*} -\frac{2998952451 \, \sqrt{10}{\left (4 \, x^{2} - 4 \, x + 1\right )} \arctan \left (\frac{\sqrt{10}{\left (20 \, x + 1\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{20 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) + 20 \,{\left (18817920 \, x^{4} + 101146320 \, x^{3} + 359461476 \, x^{2} - 1261070176 \, x + 452899509\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{46464000 \,{\left (4 \, x^{2} - 4 \, x + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.28538, size = 131, normalized size = 0.92 \begin{align*} \frac{8261577}{64000} \, \sqrt{10} \arcsin \left (\frac{1}{11} \, \sqrt{22} \sqrt{5 \, x + 3}\right ) - \frac{{\left (4 \,{\left (9801 \,{\left (12 \,{\left (8 \, \sqrt{5}{\left (5 \, x + 3\right )} + 119 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} + 27809 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} - 9996528778 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} + 164942367909 \, \sqrt{5}\right )} \sqrt{5 \, x + 3} \sqrt{-10 \, x + 5}}{1452000000 \,{\left (2 \, x - 1\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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